The number 21335
21335 is a composite number with 8 divisors. Its prime factorisation is 5 × 17 × 251. Divisors (8): 1, 5, 17, 85, 251, 1255, 4267, 21335.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
21335 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
21335 is composite. Its prime factorisation is
- 3
The divisors add up to 27216; without 21335 itself that is 5881, so 21335 is deficient (5881 is less than 21335). Euler's totient φ(21335) = 16000 numbers up to 21335 share no factor with it.
- 4
The digits of 21335 add up to 14, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 149 steps to reach 1.
LaTeX source of the formulas on this page
\[ 21335 = 5 \times 17 \times 251 \]
21335 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 27216 |
| Euler totient φ(n) | 16000 |
| Square | 455182225 |
| Cube | 9711312770375 |
| Square root | 146.065054 |
| Digit sum / digital root | 14 / 5 |
| Collatz steps to 1 | 149 |
| Scientific notation | 2.1335 × |
21335 in other forms
| Form | Value |
|---|---|
| In words | twenty-one thousand three hundred and thirty-five |
| Binary (base 2) | 101001101010111 |
| Octal (base 8) | 51527 |
| Hexadecimal (base 16) | 5357 |
| Base 3 | 1002021012 |
| As time | 21335 seconds = 5 h 55 min 35 s |
Is 21335 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | Yes (21335 ÷ 5 = 4267) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 5) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 5) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 11) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 21335 a prime number?
No. 21335 = 5 × 17 × 251, so it is divisible by 5.
What are the factors of 21335?
1, 5, 17, 85, 251, 1255, 4267, 21335.
What is 21335 in binary?
101001101010111 (hexadecimal 5357, octal 51527).
What is the square root of 21335?
About 146.0651.
Is 21335 divisible by 3?
No. Its digits add up to 14, which is not a multiple of 3.
What is special about the number 21335?
It is a composite number with 8 divisors.