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The number 21303

21303 is a composite number with 10 divisors. Its prime factorisation is 343^{4} × 263. Divisors (10): 1, 3, 9, 27, 81, 263, 789, 2367, 7101, 21303.

Number

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How to work it out

  1. 1

    What is special about 21303: a happy number: repeatedly adding the squares of its digits reaches 1; a Harshad number: divisible by its digit sum 9.

  2. 2

    21303 is composite. Its prime factorisation is

    21303=34×26321303 = 3^{4} \times 263
  3. 3

    The divisors add up to 31944; without 21303 itself that is 10641, so 21303 is deficient (10641 is less than 21303). Euler's totient φ(21303) = 14148 numbers up to 21303 share no factor with it.

  4. 4

    The digits of 21303 add up to 9, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 100 steps to reach 1.

LaTeX source of the formulas on this page
\[ 21303 = 3^{4} \times 263 \]

21303 at a glance

PropertyValue
Typecomposite
Number of divisors10
Sum of divisors31944
Euler totient φ(n)14148
Square453817809
Cube9667680785127
Square root145.955473 (= 9√263)
Digit sum / digital root9 / 9
Collatz steps to 1100
Scientific notation2.1303 × 10410^{4}

21303 in other forms

FormValue
In wordstwenty-one thousand three hundred and three
Binary (base 2)101001100110111
Octal (base 8)51467
Hexadecimal (base 16)5337
Base 31002020000
As time21303 seconds = 5 h 55 min 3 s

Is 21303 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3Yes (21303 ÷ 3 = 7101)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 3)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 2)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9Yes (21303 ÷ 9 = 2367)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 7)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 3)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 21303 a prime number?

No. 21303 = 343^{4} × 263, so it is divisible by 3.

What are the factors of 21303?

1, 3, 9, 27, 81, 263, 789, 2367, 7101, 21303.

What is 21303 in binary?

101001100110111 (hexadecimal 5337, octal 51467).

What is the square root of 21303?

About 145.9555, exactly 9√263.

Is 21303 divisible by 3?

Yes. Its digits add up to 9, a multiple of 3.

What is special about the number 21303?

21303 is a happy number: repeatedly adding the squares of its digits reaches 1; a Harshad number: divisible by its digit sum 9.

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