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The number 21253

21253 is a composite number with 4 divisors. Its prime factorisation is 53 × 401. Divisors (4): 1, 53, 401, 21253.

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How to work it out

  1. 1

    What is special about 21253: a semiprime: 53 × 401, the product of two primes.

  2. 2

    21253 is composite. Its prime factorisation is

    21253=53×40121253 = 53 \times 401
  3. 3

    The divisors add up to 21708; without 21253 itself that is 455, so 21253 is deficient (455 is less than 21253). Euler's totient φ(21253) = 20800 numbers up to 21253 share no factor with it.

  4. 4

    The digits of 21253 add up to 13, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 56 steps to reach 1.

LaTeX source of the formulas on this page
\[ 21253 = 53 \times 401 \]

21253 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors21708
Euler totient φ(n)20800
Square451690009
Cube9599767761277
Square root145.784087
Digit sum / digital root13 / 4
Collatz steps to 156
Scientific notation2.1253 × 10410^{4}

21253 in other forms

FormValue
In wordstwenty-one thousand two hundred and fifty-three
Binary (base 2)101001100000101
Octal (base 8)51405
Hexadecimal (base 16)5305
Base 31002011011
As time21253 seconds = 5 h 54 min 13 s

Is 21253 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 1)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 5)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 4)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 1)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 1)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 21253 a prime number?

No. 21253 = 53 × 401, so it is divisible by 53.

What are the factors of 21253?

1, 53, 401, 21253.

What is 21253 in binary?

101001100000101 (hexadecimal 5305, octal 51405).

What is the square root of 21253?

About 145.7841.

Is 21253 divisible by 3?

No. Its digits add up to 13, which is not a multiple of 3.

What is special about the number 21253?

21253 is a semiprime: 53 × 401, the product of two primes.

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