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The number 2023

2023 is a composite number with 6 divisors. Its prime factorisation is 7 Ɨ 17217^{2}. Divisors (6): 1, 7, 17, 119, 289, 2023.

Number

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How to work it out

  1. 1

    What is special about 2023: a Harshad number: divisible by its digit sum 7.

  2. 2

    2023 is composite. Its prime factorisation is

    2023=7Ɨ1722023 = 7 \times 17^{2}
  3. 3

    The divisors add up to 2456; without 2023 itself that is 433, so 2023 is deficient (433 is less than 2023). Euler's totient φ(2023) = 1632 numbers up to 2023 share no factor with it.

  4. 4

    The digits of 2023 add up to 7, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 156 steps to reach 1.

LaTeX source of the formulas on this page
\[ 2023 = 7 \times 17^{2} \]

2023 at a glance

PropertyValue
Typecomposite
Number of divisors6
Sum of divisors2456
Euler totient φ(n)1632
Square4092529
Cube8279186167
Square root44.977772 (= 17√7)
Digit sum / digital root7 / 7
Collatz steps to 1156
Scientific notation2.023 Ɨ 10310^{3}

2023 in other forms

FormValue
In wordstwo thousand and twenty-three
Roman numeralsMMXXIII
Binary (base 2)11111100111
Octal (base 8)3747
Hexadecimal (base 16)7E7
Base 32202221
As time2023 seconds = 33 min 43 s

Is 2023 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7Yes (2023 Ć· 7 = 289)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 7)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 10)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 7)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 2023 a prime number?

No. 2023 = 7 Ɨ 17217^{2}, so it is divisible by 7.

What are the factors of 2023?

1, 7, 17, 119, 289, 2023.

What is 2023 in binary?

11111100111 (hexadecimal 7E7, octal 3747).

What is the square root of 2023?

About 44.9778, exactly 17√7.

What is 2023 in Roman numerals?

MMXXIII.

Is 2023 divisible by 3?

No. Its digits add up to 7, which is not a multiple of 3.

What is special about the number 2023?

2023 is a Harshad number: divisible by its digit sum 7.

All about 2023

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    2023: is it prime? Factors, square root, binary, Roman numeral | WordGPT