The number 20223
20223 is a composite number with 16 divisors. Its prime factorisation is × 7 × 107. Divisors (16): 1, 3, 7, 9, 21, 27, 63, 107, 189, 321, 749, 963, 2247, 2889, 6741, 20223.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 20223: a Harshad number: divisible by its digit sum 9.
- 2
20223 is composite. Its prime factorisation is
- 3
The divisors add up to 34560; without 20223 itself that is 14337, so 20223 is deficient (14337 is less than 20223). Euler's totient φ(20223) = 11448 numbers up to 20223 share no factor with it.
- 4
The digits of 20223 add up to 9, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 87 steps to reach 1.
LaTeX source of the formulas on this page
\[ 20223 = 3^{3} \times 7 \times 107 \]20223 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 16 |
| Sum of divisors | 34560 |
| Euler totient φ(n) | 11448 |
| Square | 408969729 |
| Cube | 8270594829567 |
| Square root | 142.207595 (= 3√2247) |
| Digit sum / digital root | 9 / 9 |
| Collatz steps to 1 | 87 |
| Scientific notation | 2.0223 × |
20223 in other forms
| Form | Value |
|---|---|
| In words | twenty thousand two hundred and twenty-three |
| Binary (base 2) | 100111011111111 |
| Octal (base 8) | 47377 |
| Hexadecimal (base 16) | 4EFF |
| Base 3 | 1000202000 |
| As time | 20223 seconds = 5 h 37 min 3 s |
Is 20223 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (20223 ÷ 3 = 6741) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (20223 ÷ 7 = 2889) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (20223 ÷ 9 = 2247) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 5) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 20223 a prime number?
No. 20223 = × 7 × 107, so it is divisible by 3.
What are the factors of 20223?
1, 3, 7, 9, 21, 27, 63, 107, 189, 321, 749, 963, 2247, 2889, 6741, 20223.
What is 20223 in binary?
100111011111111 (hexadecimal 4EFF, octal 47377).
What is the square root of 20223?
About 142.2076, exactly 3√2247.
Is 20223 divisible by 3?
Yes. Its digits add up to 9, a multiple of 3.
What is special about the number 20223?
20223 is a Harshad number: divisible by its digit sum 9.