The number 20048
20048 is a composite number with 20 divisors. Its prime factorisation is × 7 × 179. Divisors (20): 1, 2, 4, 7, 8, 14, 16, 28, 56, 112, 179, 358, 716, 1253, 1432, 2506 … 20048.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 20048: a Harshad number: divisible by its digit sum 14.
- 2
20048 is composite. Its prime factorisation is
- 3
The divisors add up to 44640; without 20048 itself that is 24592, so 20048 is abundant (24592 is more than 20048). Euler's totient φ(20048) = 8544 numbers up to 20048 share no factor with it.
- 4
The digits of 20048 add up to 14, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 136 steps to reach 1.
LaTeX source of the formulas on this page
\[ 20048 = 2^{4} \times 7 \times 179 \]20048 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 20 |
| Sum of divisors | 44640 |
| Euler totient φ(n) | 8544 |
| Square | 401922304 |
| Cube | 8057738350592 |
| Square root | 141.590960 (= 4√1253) |
| Digit sum / digital root | 14 / 5 |
| Collatz steps to 1 | 136 |
| Scientific notation | 2.0048 × |
20048 in other forms
| Form | Value |
|---|---|
| In words | twenty thousand and forty-eight |
| Binary (base 2) | 100111001010000 |
| Octal (base 8) | 47120 |
| Hexadecimal (base 16) | 4E50 |
| Base 3 | 1000111112 |
| As time | 20048 seconds = 5 h 34 min 8 s |
Is 20048 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | Yes (20048 ÷ 2 = 10024) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | Yes (20048 ÷ 4 = 5012) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 2) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | Yes (20048 ÷ 7 = 2864) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | Yes (20048 ÷ 8 = 2506) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 5) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 8) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 8) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 20048 a prime number?
No. 20048 = × 7 × 179, so it is divisible by 2.
What are the factors of 20048?
1, 2, 4, 7, 8, 14, 16, 28, 56, 112, 179, 358, 716, 1253, 1432, 2506, 2864, 5012, 10024, 20048.
What is 20048 in binary?
100111001010000 (hexadecimal 4E50, octal 47120).
What is the square root of 20048?
About 141.5910, exactly 4√1253.
Is 20048 divisible by 3?
No. Its digits add up to 14, which is not a multiple of 3.
What is special about the number 20048?
20048 is a Harshad number: divisible by its digit sum 14.