The number 20033
20033 is a composite number with 8 divisors. Its prime factorisation is 13 × 23 × 67. Divisors (8): 1, 13, 23, 67, 299, 871, 1541, 20033.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
20033 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
20033 is composite. Its prime factorisation is
- 3
The divisors add up to 22848; without 20033 itself that is 2815, so 20033 is deficient (2815 is less than 20033). Euler's totient φ(20033) = 17424 numbers up to 20033 share no factor with it.
- 4
The digits of 20033 add up to 8, and repeating that until one digit is left gives the digital root 8. The Collatz sequence (halve if even, else 3n+1) takes 92 steps to reach 1.
LaTeX source of the formulas on this page
\[ 20033 = 13 \times 23 \times 67 \]
20033 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 8 |
| Sum of divisors | 22848 |
| Euler totient φ(n) | 17424 |
| Square | 401321089 |
| Cube | 8039665375937 |
| Square root | 141.537981 |
| Digit sum / digital root | 8 / 8 |
| Collatz steps to 1 | 92 |
| Scientific notation | 2.0033 × |
20033 in other forms
| Form | Value |
|---|---|
| In words | twenty thousand and thirty-three |
| Binary (base 2) | 100111001000001 |
| Octal (base 8) | 47101 |
| Hexadecimal (base 16) | 4E41 |
| Base 3 | 1000110222 |
| As time | 20033 seconds = 5 h 33 min 53 s |
Is 20033 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 8) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 20033 a prime number?
No. 20033 = 13 × 23 × 67, so it is divisible by 13.
What are the factors of 20033?
1, 13, 23, 67, 299, 871, 1541, 20033.
What is 20033 in binary?
100111001000001 (hexadecimal 4E41, octal 47101).
What is the square root of 20033?
About 141.5380.
Is 20033 divisible by 3?
No. Its digits add up to 8, which is not a multiple of 3.
What is special about the number 20033?
It is a composite number with 8 divisors.