The number 19983
19983 is a composite number with 4 divisors. Its prime factorisation is 3 × 6661. Divisors (4): 1, 3, 6661, 19983.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 19983: a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 3 × 6661, the product of two primes.
- 2
19983 is composite. Its prime factorisation is
- 3
The divisors add up to 26648; without 19983 itself that is 6665, so 19983 is deficient (6665 is less than 19983). Euler's totient φ(19983) = 13320 numbers up to 19983 share no factor with it.
- 4
The digits of 19983 add up to 30, and repeating that until one digit is left gives the digital root 3. The Collatz sequence (halve if even, else 3n+1) takes 167 steps to reach 1.
LaTeX source of the formulas on this page
\[ 19983 = 3 \times 6661 \]
19983 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 26648 |
| Euler totient φ(n) | 13320 |
| Square | 399320289 |
| Cube | 7979617335087 |
| Square root | 141.361239 |
| Digit sum / digital root | 30 / 3 |
| Collatz steps to 1 | 167 |
| Scientific notation | 1.9983 × |
19983 in other forms
| Form | Value |
|---|---|
| In words | nineteen thousand nine hundred and eighty-three |
| Binary (base 2) | 100111000001111 |
| Octal (base 8) | 47017 |
| Hexadecimal (base 16) | 4E0F |
| Base 3 | 1000102010 |
| As time | 19983 seconds = 5 h 33 min 3 s |
Is 19983 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (19983 ÷ 3 = 6661) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 3) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 7) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 19983 a prime number?
No. 19983 = 3 × 6661, so it is divisible by 3.
What are the factors of 19983?
1, 3, 6661, 19983.
What is 19983 in binary?
100111000001111 (hexadecimal 4E0F, octal 47017).
What is the square root of 19983?
About 141.3612.
Is 19983 divisible by 3?
Yes. Its digits add up to 30, a multiple of 3.
What is special about the number 19983?
19983 is a happy number: repeatedly adding the squares of its digits reaches 1; a semiprime: 3 × 6661, the product of two primes.