The number 19683
19683 is a perfect power (). Its prime factorisation is . Divisors (10): 1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 19683: a perfect power (); a Harshad number: divisible by its digit sum 27.
- 2
19683 is composite. Its prime factorisation is
- 3
The divisors add up to 29524; without 19683 itself that is 9841, so 19683 is deficient (9841 is less than 19683). Euler's totient φ(19683) = 13122 numbers up to 19683 share no factor with it.
- 4
The digits of 19683 add up to 27, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 43 steps to reach 1.
LaTeX source of the formulas on this page
\[ 19683 = 3^{9} \]19683 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 10 |
| Sum of divisors | 29524 |
| Euler totient φ(n) | 13122 |
| Square | 387420489 |
| Cube | 7625597484987 |
| Square root | 140.296115 (= 81√3) |
| Digit sum / digital root | 27 / 9 |
| Collatz steps to 1 | 43 |
| Scientific notation | 1.9683 × |
| Perfect power |
19683 in other forms
| Form | Value |
|---|---|
| In words | nineteen thousand six hundred and eighty-three |
| Binary (base 2) | 100110011100011 |
| Octal (base 8) | 46343 |
| Hexadecimal (base 16) | 4CE3 |
| Base 3 | 1000000000 |
| As time | 19683 seconds = 5 h 28 min 3 s |
Is 19683 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (19683 ÷ 3 = 6561) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (19683 ÷ 9 = 2187) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 4) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 19683 a prime number?
No. 19683 = , so it is divisible by 3.
What are the factors of 19683?
1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683.
What is 19683 in binary?
100110011100011 (hexadecimal 4CE3, octal 46343).
What is the square root of 19683?
About 140.2961, exactly 81√3.
Is 19683 divisible by 3?
Yes. Its digits add up to 27, a multiple of 3.
What is special about the number 19683?
19683 is a perfect power (); a Harshad number: divisible by its digit sum 27.