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The number 18823

18823 is a composite number with 4 divisors. Its prime factorisation is 7 × 2689. Divisors (4): 1, 7, 2689, 18823.

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How to work it out

  1. 1

    What is special about 18823: a semiprime: 7 × 2689, the product of two primes.

  2. 2

    18823 is composite. Its prime factorisation is

    18823=7×268918823 = 7 \times 2689
  3. 3

    The divisors add up to 21520; without 18823 itself that is 2697, so 18823 is deficient (2697 is less than 18823). Euler's totient φ(18823) = 16128 numbers up to 18823 share no factor with it.

  4. 4

    The digits of 18823 add up to 22, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 61 steps to reach 1.

LaTeX source of the formulas on this page
\[ 18823 = 7 \times 2689 \]

18823 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors21520
Euler totient φ(n)16128
Square354305329
Cube6669089207767
Square root137.196939
Digit sum / digital root22 / 4
Collatz steps to 161
Scientific notation1.8823 × 10410^{4}

18823 in other forms

FormValue
In wordseighteen thousand eight hundred and twenty-three
Binary (base 2)100100110000111
Octal (base 8)44607
Hexadecimal (base 16)4987
Base 3221211011
As time18823 seconds = 5 h 13 min 43 s

Is 18823 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7Yes (18823 ÷ 7 = 2689)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 4)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 2)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 7)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 18823 a prime number?

No. 18823 = 7 × 2689, so it is divisible by 7.

What are the factors of 18823?

1, 7, 2689, 18823.

What is 18823 in binary?

100100110000111 (hexadecimal 4987, octal 44607).

What is the square root of 18823?

About 137.1969.

Is 18823 divisible by 3?

No. Its digits add up to 22, which is not a multiple of 3.

What is special about the number 18823?

18823 is a semiprime: 7 × 2689, the product of two primes.

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