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The number 18391

18391 is a composite number with 4 divisors. Its prime factorisation is 53 × 347. Divisors (4): 1, 53, 347, 18391.

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How to work it out

  1. 1

    What is special about 18391: a semiprime: 53 × 347, the product of two primes.

  2. 2

    18391 is composite. Its prime factorisation is

    18391=53×34718391 = 53 \times 347
  3. 3

    The divisors add up to 18792; without 18391 itself that is 401, so 18391 is deficient (401 is less than 18391). Euler's totient φ(18391) = 17992 numbers up to 18391 share no factor with it.

  4. 4

    The digits of 18391 add up to 22, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 154 steps to reach 1.

LaTeX source of the formulas on this page
\[ 18391 = 53 \times 347 \]

18391 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors18792
Euler totient φ(n)17992
Square338228881
Cube6220367350471
Square root135.613421
Digit sum / digital root22 / 4
Collatz steps to 1154
Scientific notation1.8391 × 10410^{4}

18391 in other forms

FormValue
In wordseighteen thousand three hundred and ninety-one
Binary (base 2)100011111010111
Octal (base 8)43727
Hexadecimal (base 16)47D7
Base 3221020011
As time18391 seconds = 5 h 6 min 31 s

Is 18391 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 1)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 2)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 4)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 1)A number is divisible by 10 if the last digit is 0.
11No (remainder 10)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 7)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 18391 a prime number?

No. 18391 = 53 × 347, so it is divisible by 53.

What are the factors of 18391?

1, 53, 347, 18391.

What is 18391 in binary?

100011111010111 (hexadecimal 47D7, octal 43727).

What is the square root of 18391?

About 135.6134.

Is 18391 divisible by 3?

No. Its digits add up to 22, which is not a multiple of 3.

What is special about the number 18391?

18391 is a semiprime: 53 × 347, the product of two primes.

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