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The number 18023

18023 is a composite number with 4 divisors. Its prime factorisation is 67 × 269. Divisors (4): 1, 67, 269, 18023.

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How to work it out

  1. 1

    What is special about 18023: a semiprime: 67 × 269, the product of two primes.

  2. 2

    18023 is composite. Its prime factorisation is

    18023=67×26918023 = 67 \times 269
  3. 3

    The divisors add up to 18360; without 18023 itself that is 337, so 18023 is deficient (337 is less than 18023). Euler's totient φ(18023) = 17688 numbers up to 18023 share no factor with it.

  4. 4

    The digits of 18023 add up to 14, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 92 steps to reach 1.

LaTeX source of the formulas on this page
\[ 18023 = 67 \times 269 \]

18023 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors18360
Euler totient φ(n)17688
Square324828529
Cube5854384578167
Square root134.249767
Digit sum / digital root14 / 5
Collatz steps to 192
Scientific notation1.8023 × 10410^{4}

18023 in other forms

FormValue
In wordseighteen thousand and twenty-three
Binary (base 2)100011001100111
Octal (base 8)43147
Hexadecimal (base 16)4667
Base 3220201112
As time18023 seconds = 5 h 0 min 23 s

Is 18023 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 5)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 5)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 5)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 11)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 18023 a prime number?

No. 18023 = 67 × 269, so it is divisible by 67.

What are the factors of 18023?

1, 67, 269, 18023.

What is 18023 in binary?

100011001100111 (hexadecimal 4667, octal 43147).

What is the square root of 18023?

About 134.2498.

Is 18023 divisible by 3?

No. Its digits add up to 14, which is not a multiple of 3.

What is special about the number 18023?

18023 is a semiprime: 67 × 269, the product of two primes.

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