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The number 17023

17023 is a composite number with 4 divisors. Its prime factorisation is 29 × 587. Divisors (4): 1, 29, 587, 17023.

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How to work it out

  1. 1

    What is special about 17023: a semiprime: 29 × 587, the product of two primes.

  2. 2

    17023 is composite. Its prime factorisation is

    17023=29×58717023 = 29 \times 587
  3. 3

    The divisors add up to 17640; without 17023 itself that is 617, so 17023 is deficient (617 is less than 17023). Euler's totient φ(17023) = 16408 numbers up to 17023 share no factor with it.

  4. 4

    The digits of 17023 add up to 13, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 216 steps to reach 1.

LaTeX source of the formulas on this page
\[ 17023 = 29 \times 587 \]

17023 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors17640
Euler totient φ(n)16408
Square289782529
Cube4932967991167
Square root130.472219
Digit sum / digital root13 / 4
Collatz steps to 1216
Scientific notation1.7023 × 10410^{4}

17023 in other forms

FormValue
In wordsseventeen thousand and twenty-three
Binary (base 2)100001001111111
Octal (base 8)41177
Hexadecimal (base 16)427F
Base 3212100111
As time17023 seconds = 4 h 43 min 43 s

Is 17023 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 6)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 4)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 6)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 7)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 17023 a prime number?

No. 17023 = 29 × 587, so it is divisible by 29.

What are the factors of 17023?

1, 29, 587, 17023.

What is 17023 in binary?

100001001111111 (hexadecimal 427F, octal 41177).

What is the square root of 17023?

About 130.4722.

Is 17023 divisible by 3?

No. Its digits add up to 13, which is not a multiple of 3.

What is special about the number 17023?

17023 is a semiprime: 29 × 587, the product of two primes.

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