The number 16393
16393 is a composite number with 6 divisors. Its prime factorisation is Ć 97. Divisors (6): 1, 13, 97, 169, 1261, 16393.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
16393 has no famous special property in the usual lists (prime, square, cube, triangular, Fibonacci, palindrome, perfect), but it is still a composite number.
- 2
16393 is composite. Its prime factorisation is
- 3
The divisors add up to 17934; without 16393 itself that is 1541, so 16393 is deficient (1541 is less than 16393). Euler's totient Ļ(16393) = 14976 numbers up to 16393 share no factor with it.
- 4
The digits of 16393 add up to 22, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 53 steps to reach 1.
LaTeX source of the formulas on this page
\[ 16393 = 13^{2} \times 97 \]16393 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 6 |
| Sum of divisors | 17934 |
| Euler totient Ļ(n) | 14976 |
| Square | 268730449 |
| Cube | 4405298250457 |
| Square root | 128.035151 (= 13ā97) |
| Digit sum / digital root | 22 / 4 |
| Collatz steps to 1 | 53 |
| Scientific notation | 1.6393 Ć |
16393 in other forms
| Form | Value |
|---|---|
| In words | sixteen thousand three hundred and ninety-three |
| Binary (base 2) | 100000000001001 |
| Octal (base 8) | 40011 |
| Hexadecimal (base 16) | 4009 |
| Base 3 | 211111011 |
| As time | 16393 seconds = 4 h 33 min 13 s |
Is 16393 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 1) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 16393 a prime number?
No. 16393 = Ć 97, so it is divisible by 13.
What are the factors of 16393?
1, 13, 97, 169, 1261, 16393.
What is 16393 in binary?
100000000001001 (hexadecimal 4009, octal 40011).
What is the square root of 16393?
About 128.0352, exactly 13ā97.
Is 16393 divisible by 3?
No. Its digits add up to 22, which is not a multiple of 3.
What is special about the number 16393?
It is a composite number with 6 divisors.