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The number 15023

15023 is a composite number with 4 divisors. Its prime factorisation is 83 × 181. Divisors (4): 1, 83, 181, 15023.

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How to work it out

  1. 1

    What is special about 15023: a semiprime: 83 × 181, the product of two primes.

  2. 2

    15023 is composite. Its prime factorisation is

    15023=83×18115023 = 83 \times 181
  3. 3

    The divisors add up to 15288; without 15023 itself that is 265, so 15023 is deficient (265 is less than 15023). Euler's totient φ(15023) = 14760 numbers up to 15023 share no factor with it.

  4. 4

    The digits of 15023 add up to 11, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 63 steps to reach 1.

LaTeX source of the formulas on this page
\[ 15023 = 83 \times 181 \]

15023 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors15288
Euler totient φ(n)14760
Square225690529
Cube3390548817167
Square root122.568348
Digit sum / digital root11 / 2
Collatz steps to 163
Scientific notation1.5023 × 10410^{4}

15023 in other forms

FormValue
In wordsfifteen thousand and twenty-three
Binary (base 2)11101010101111
Octal (base 8)35257
Hexadecimal (base 16)3AAF
Base 3202121102
As time15023 seconds = 4 h 10 min 23 s

Is 15023 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 1)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 7)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 2)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 8)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 11)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 15023 a prime number?

No. 15023 = 83 × 181, so it is divisible by 83.

What are the factors of 15023?

1, 83, 181, 15023.

What is 15023 in binary?

11101010101111 (hexadecimal 3AAF, octal 35257).

What is the square root of 15023?

About 122.5683.

Is 15023 divisible by 3?

No. Its digits add up to 11, which is not a multiple of 3.

What is special about the number 15023?

15023 is a semiprime: 83 × 181, the product of two primes.

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