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The number 14477

14477 is a composite number with 4 divisors. Its prime factorisation is 31 × 467. Divisors (4): 1, 31, 467, 14477.

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How to work it out

  1. 1

    What is special about 14477: a semiprime: 31 × 467, the product of two primes.

  2. 2

    14477 is composite. Its prime factorisation is

    14477=31×46714477 = 31 \times 467
  3. 3

    The divisors add up to 14976; without 14477 itself that is 499, so 14477 is deficient (499 is less than 14477). Euler's totient φ(14477) = 13980 numbers up to 14477 share no factor with it.

  4. 4

    The digits of 14477 add up to 23, and repeating that until one digit is left gives the digital root 5. The Collatz sequence (halve if even, else 3n+1) takes 58 steps to reach 1.

LaTeX source of the formulas on this page
\[ 14477 = 31 \times 467 \]

14477 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors14976
Euler totient φ(n)13980
Square209583529
Cube3034140749333
Square root120.320406
Digit sum / digital root23 / 5
Collatz steps to 158
Scientific notation1.4477 × 10410^{4}

14477 in other forms

FormValue
In wordsfourteen thousand four hundred and seventy-seven
Binary (base 2)11100010001101
Octal (base 8)34215
Hexadecimal (base 16)388D
Base 3201212012
As time14477 seconds = 4 h 1 min 17 s

Is 14477 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 2)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 1)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 2)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 5)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 1)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 5)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 5)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 7)A number is divisible by 10 if the last digit is 0.
11No (remainder 1)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 5)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 14477 a prime number?

No. 14477 = 31 × 467, so it is divisible by 31.

What are the factors of 14477?

1, 31, 467, 14477.

What is 14477 in binary?

11100010001101 (hexadecimal 388D, octal 34215).

What is the square root of 14477?

About 120.3204.

Is 14477 divisible by 3?

No. Its digits add up to 23, which is not a multiple of 3.

What is special about the number 14477?

14477 is a semiprime: 31 × 467, the product of two primes.

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