The number 13943
13943 is a composite number with 4 divisors. Its prime factorisation is 73 × 191. Divisors (4): 1, 73, 191, 13943.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 13943: a semiprime: 73 × 191, the product of two primes.
- 2
13943 is composite. Its prime factorisation is
- 3
The divisors add up to 14208; without 13943 itself that is 265, so 13943 is deficient (265 is less than 13943). Euler's totient φ(13943) = 13680 numbers up to 13943 share no factor with it.
- 4
The digits of 13943 add up to 20, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 58 steps to reach 1.
LaTeX source of the formulas on this page
\[ 13943 = 73 \times 191 \]
13943 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 14208 |
| Euler totient φ(n) | 13680 |
| Square | 194407249 |
| Cube | 2710620272807 |
| Square root | 118.080481 |
| Digit sum / digital root | 20 / 2 |
| Collatz steps to 1 | 58 |
| Scientific notation | 1.3943 × |
13943 in other forms
| Form | Value |
|---|---|
| In words | thirteen thousand nine hundred and forty-three |
| Binary (base 2) | 11011001110111 |
| Octal (base 8) | 33167 |
| Hexadecimal (base 16) | 3677 |
| Base 3 | 201010102 |
| As time | 13943 seconds = 3 h 52 min 23 s |
Is 13943 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 6) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 6) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 11) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 13943 a prime number?
No. 13943 = 73 × 191, so it is divisible by 73.
What are the factors of 13943?
1, 73, 191, 13943.
What is 13943 in binary?
11011001110111 (hexadecimal 3677, octal 33167).
What is the square root of 13943?
About 118.0805.
Is 13943 divisible by 3?
No. Its digits add up to 20, which is not a multiple of 3.
What is special about the number 13943?
13943 is a semiprime: 73 × 191, the product of two primes.