The number 13939
13939 is a composite number with 4 divisors. Its prime factorisation is 53 × 263. Divisors (4): 1, 53, 263, 13939.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 13939: a semiprime: 53 × 263, the product of two primes.
- 2
13939 is composite. Its prime factorisation is
- 3
The divisors add up to 14256; without 13939 itself that is 317, so 13939 is deficient (317 is less than 13939). Euler's totient φ(13939) = 13624 numbers up to 13939 share no factor with it.
- 4
The digits of 13939 add up to 25, and repeating that until one digit is left gives the digital root 7. The Collatz sequence (halve if even, else 3n+1) takes 58 steps to reach 1.
LaTeX source of the formulas on this page
\[ 13939 = 53 \times 263 \]
13939 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 14256 |
| Euler totient φ(n) | 13624 |
| Square | 194295721 |
| Cube | 2708288055019 |
| Square root | 118.063542 |
| Digit sum / digital root | 25 / 7 |
| Collatz steps to 1 | 58 |
| Scientific notation | 1.3939 × |
13939 in other forms
| Form | Value |
|---|---|
| In words | thirteen thousand nine hundred and thirty-nine |
| Binary (base 2) | 11011001110011 |
| Octal (base 8) | 33163 |
| Hexadecimal (base 16) | 3673 |
| Base 3 | 201010021 |
| As time | 13939 seconds = 3 h 52 min 19 s |
Is 13939 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 4) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 2) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 7) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 9) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 2) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 13939 a prime number?
No. 13939 = 53 × 263, so it is divisible by 53.
What are the factors of 13939?
1, 53, 263, 13939.
What is 13939 in binary?
11011001110011 (hexadecimal 3673, octal 33163).
What is the square root of 13939?
About 118.0635.
Is 13939 divisible by 3?
No. Its digits add up to 25, which is not a multiple of 3.
What is special about the number 13939?
13939 is a semiprime: 53 × 263, the product of two primes.