The number 13924

No. 13924 = 2^2 × 59^2, so it is divisible by 2.

13924 is a perfect square (118²). Its prime factorisation is $2^{2}$ × $59^{2}$ . Divisors (9): 1, 2, 4, 59, 118, 236, 3481, 6962, 13924.

Number

Pick any whole number from 1 to 100,000.

13924 = 2^{2} \times 59^{2}

How to work it out

1
What is special about 13924: a perfect square (118²).
2
13924 is composite. Its prime factorisation is
$13924 = 2^{2} \times 59^{2}$
3
The divisors add up to 24787; without 13924 itself that is 10863, so 13924 is deficient (10863 is less than 13924). Euler's totient φ(13924) = 6844 numbers up to 13924 share no factor with it.
4
The digits of 13924 add up to 19, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 58 steps to reach 1.

LaTeX source of the formulas on this page

\[ 13924 = 2^{2} \times 59^{2} \]

Form	Value
In words	thirteen thousand nine hundred and twenty-four
Binary (base 2)	11011001100100
Octal (base 8)	33144
Hexadecimal (base 16)	3664
Base 3	201002201
As time	13924 seconds = 3 h 52 min 4 s

Divisor	Answer	Rule
2	Yes (13924 ÷ 2 = 6962)	A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3	No (remainder 1)	A number is divisible by 3 if the digits add up to a multiple of 3.
4	Yes (13924 ÷ 4 = 3481)	A number is divisible by 4 if the last two digits make a multiple of 4.
5	No (remainder 4)	A number is divisible by 5 if the last digit is 0 or 5.
6	No (remainder 4)	A number is divisible by 6 if it is divisible by both 2 and 3.
7	No (remainder 1)	A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8	No (remainder 4)	A number is divisible by 8 if the last three digits make a multiple of 8.
9	No (remainder 1)	A number is divisible by 9 if the digits add up to a multiple of 9.
10	No (remainder 4)	A number is divisible by 10 if the last digit is 0.
11	No (remainder 9)	A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12	No (remainder 4)	A number is divisible by 12 if it is divisible by both 3 and 4.

Is 13924 a prime number?

No. 13924 = $2^{2}$ × $59^{2}$ , so it is divisible by 2.

What are the factors of 13924?

1, 2, 4, 59, 118, 236, 3481, 6962, 13924.

What is 13924 in binary?

11011001100100 (hexadecimal 3664, octal 33144).

What is the square root of 13924?

118, because 118 × 118 = 13924.

Is 13924 divisible by 3?

No. Its digits add up to 19, which is not a multiple of 3.

What is special about the number 13924?

13924 is a perfect square (118²).