The number 13423
13423 is a composite number with 4 divisors. Its prime factorisation is 31 × 433. Divisors (4): 1, 31, 433, 13423.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 13423: a semiprime: 31 × 433, the product of two primes.
- 2
13423 is composite. Its prime factorisation is
- 3
The divisors add up to 13888; without 13423 itself that is 465, so 13423 is deficient (465 is less than 13423). Euler's totient φ(13423) = 12960 numbers up to 13423 share no factor with it.
- 4
The digits of 13423 add up to 13, and repeating that until one digit is left gives the digital root 4. The Collatz sequence (halve if even, else 3n+1) takes 213 steps to reach 1.
LaTeX source of the formulas on this page
\[ 13423 = 31 \times 433 \]
13423 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 13888 |
| Euler totient φ(n) | 12960 |
| Square | 180176929 |
| Cube | 2418514917967 |
| Square root | 115.857671 |
| Digit sum / digital root | 13 / 4 |
| Collatz steps to 1 | 213 |
| Scientific notation | 1.3423 × |
13423 in other forms
| Form | Value |
|---|---|
| In words | thirteen thousand four hundred and twenty-three |
| Binary (base 2) | 11010001101111 |
| Octal (base 8) | 32157 |
| Hexadecimal (base 16) | 346F |
| Base 3 | 200102011 |
| As time | 13423 seconds = 3 h 43 min 43 s |
Is 13423 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 1) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 3) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 1) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 7) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 4) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 3) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 7) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 13423 a prime number?
No. 13423 = 31 × 433, so it is divisible by 31.
What are the factors of 13423?
1, 31, 433, 13423.
What is 13423 in binary?
11010001101111 (hexadecimal 346F, octal 32157).
What is the square root of 13423?
About 115.8577.
Is 13423 divisible by 3?
No. Its digits add up to 13, which is not a multiple of 3.
What is special about the number 13423?
13423 is a semiprime: 31 × 433, the product of two primes.