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The number 12403

12403 is a triangular number: 1 + 2 + … + 157 = 12403. Its prime factorisation is 79 × 157. Divisors (4): 1, 79, 157, 12403.

Number

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How to work it out

  1. 1

    What is special about 12403: a triangular number: 1 + 2 + … + 157 = 12403; a semiprime: 79 × 157, the product of two primes.

  2. 2

    12403 is composite. Its prime factorisation is

    12403=79×15712403 = 79 \times 157
  3. 3

    The divisors add up to 12640; without 12403 itself that is 237, so 12403 is deficient (237 is less than 12403). Euler's totient φ(12403) = 12168 numbers up to 12403 share no factor with it.

  4. 4

    The digits of 12403 add up to 10, and repeating that until one digit is left gives the digital root 1. The Collatz sequence (halve if even, else 3n+1) takes 37 steps to reach 1.

LaTeX source of the formulas on this page
\[ 12403 = 79 \times 157 \]

12403 at a glance

PropertyValue
Typecomposite
Number of divisors4
Sum of divisors12640
Euler totient φ(n)12168
Square153834409
Cube1908008174827
Square root111.368757
Digit sum / digital root10 / 1
Collatz steps to 137
Scientific notation1.2403 × 10410^{4}

12403 in other forms

FormValue
In wordstwelve thousand four hundred and three
Binary (base 2)11000001110011
Octal (base 8)30163
Hexadecimal (base 16)3073
Base 3122000101
As time12403 seconds = 3 h 26 min 43 s

Is 12403 divisible by 2 to 12?

DivisorAnswerRule
2No (remainder 1)A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8).
3No (remainder 1)A number is divisible by 3 if the digits add up to a multiple of 3.
4No (remainder 3)A number is divisible by 4 if the last two digits make a multiple of 4.
5No (remainder 3)A number is divisible by 5 if the last digit is 0 or 5.
6No (remainder 1)A number is divisible by 6 if it is divisible by both 2 and 3.
7No (remainder 6)A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7.
8No (remainder 3)A number is divisible by 8 if the last three digits make a multiple of 8.
9No (remainder 1)A number is divisible by 9 if the digits add up to a multiple of 9.
10No (remainder 3)A number is divisible by 10 if the last digit is 0.
11No (remainder 6)A number is divisible by 11 if the alternating sum of the digits is a multiple of 11.
12No (remainder 7)A number is divisible by 12 if it is divisible by both 3 and 4.

Questions

Is 12403 a prime number?

No. 12403 = 79 × 157, so it is divisible by 79.

What are the factors of 12403?

1, 79, 157, 12403.

What is 12403 in binary?

11000001110011 (hexadecimal 3073, octal 30163).

What is the square root of 12403?

About 111.3688.

Is 12403 divisible by 3?

No. Its digits add up to 10, which is not a multiple of 3.

What is special about the number 12403?

12403 is a triangular number: 1 + 2 + … + 157 = 12403; a semiprime: 79 × 157, the product of two primes.

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