The number 12017
12017 is a composite number with 4 divisors. Its prime factorisation is 61 × 197. Divisors (4): 1, 61, 197, 12017.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 12017: a semiprime: 61 × 197, the product of two primes.
- 2
12017 is composite. Its prime factorisation is
- 3
The divisors add up to 12276; without 12017 itself that is 259, so 12017 is deficient (259 is less than 12017). Euler's totient φ(12017) = 11760 numbers up to 12017 share no factor with it.
- 4
The digits of 12017 add up to 11, and repeating that until one digit is left gives the digital root 2. The Collatz sequence (halve if even, else 3n+1) takes 50 steps to reach 1.
LaTeX source of the formulas on this page
\[ 12017 = 61 \times 197 \]
12017 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 4 |
| Sum of divisors | 12276 |
| Euler totient φ(n) | 11760 |
| Square | 144408289 |
| Cube | 1735354408913 |
| Square root | 109.622078 |
| Digit sum / digital root | 11 / 2 |
| Collatz steps to 1 | 50 |
| Scientific notation | 1.2017 × |
12017 in other forms
| Form | Value |
|---|---|
| In words | twelve thousand and seventeen |
| Binary (base 2) | 10111011110001 |
| Octal (base 8) | 27361 |
| Hexadecimal (base 16) | 2EF1 |
| Base 3 | 121111002 |
| As time | 12017 seconds = 3 h 20 min 17 s |
Is 12017 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | No (remainder 2) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 1) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | No (remainder 2) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 5) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 5) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 1) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | No (remainder 2) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 7) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 5) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 5) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 12017 a prime number?
No. 12017 = 61 × 197, so it is divisible by 61.
What are the factors of 12017?
1, 61, 197, 12017.
What is 12017 in binary?
10111011110001 (hexadecimal 2EF1, octal 27361).
What is the square root of 12017?
About 109.6221.
Is 12017 divisible by 3?
No. Its digits add up to 11, which is not a multiple of 3.
What is special about the number 12017?
12017 is a semiprime: 61 × 197, the product of two primes.