The number 10035
10035 is a composite number with 12 divisors. Its prime factorisation is × 5 × 223. Divisors (12): 1, 3, 5, 9, 15, 45, 223, 669, 1115, 2007, 3345, 10035.
Pick any whole number from 1 to 100,000.
How to work it out
- 1
What is special about 10035: a Harshad number: divisible by its digit sum 9.
- 2
10035 is composite. Its prime factorisation is
- 3
The divisors add up to 17472; without 10035 itself that is 7437, so 10035 is deficient (7437 is less than 10035). Euler's totient φ(10035) = 5328 numbers up to 10035 share no factor with it.
- 4
The digits of 10035 add up to 9, and repeating that until one digit is left gives the digital root 9. The Collatz sequence (halve if even, else 3n+1) takes 42 steps to reach 1.
LaTeX source of the formulas on this page
\[ 10035 = 3^{2} \times 5 \times 223 \]10035 at a glance
| Property | Value |
|---|---|
| Type | composite |
| Number of divisors | 12 |
| Sum of divisors | 17472 |
| Euler totient φ(n) | 5328 |
| Square | 100701225 |
| Cube | 1010536792875 |
| Square root | 100.174847 (= 3√1115) |
| Digit sum / digital root | 9 / 9 |
| Collatz steps to 1 | 42 |
| Scientific notation | 1.0035 × |
10035 in other forms
| Form | Value |
|---|---|
| In words | ten thousand and thirty-five |
| Binary (base 2) | 10011100110011 |
| Octal (base 8) | 23463 |
| Hexadecimal (base 16) | 2733 |
| Base 3 | 111202200 |
| As time | 10035 seconds = 2 h 47 min 15 s |
Is 10035 divisible by 2 to 12?
| Divisor | Answer | Rule |
|---|---|---|
| 2 | No (remainder 1) | A number is divisible by 2 if the last digit is even (0, 2, 4, 6, 8). |
| 3 | Yes (10035 ÷ 3 = 3345) | A number is divisible by 3 if the digits add up to a multiple of 3. |
| 4 | No (remainder 3) | A number is divisible by 4 if the last two digits make a multiple of 4. |
| 5 | Yes (10035 ÷ 5 = 2007) | A number is divisible by 5 if the last digit is 0 or 5. |
| 6 | No (remainder 3) | A number is divisible by 6 if it is divisible by both 2 and 3. |
| 7 | No (remainder 4) | A number is divisible by 7 if double the last digit and subtract it from the rest: the result is a multiple of 7. |
| 8 | No (remainder 3) | A number is divisible by 8 if the last three digits make a multiple of 8. |
| 9 | Yes (10035 ÷ 9 = 1115) | A number is divisible by 9 if the digits add up to a multiple of 9. |
| 10 | No (remainder 5) | A number is divisible by 10 if the last digit is 0. |
| 11 | No (remainder 3) | A number is divisible by 11 if the alternating sum of the digits is a multiple of 11. |
| 12 | No (remainder 3) | A number is divisible by 12 if it is divisible by both 3 and 4. |
Questions
Is 10035 a prime number?
No. 10035 = × 5 × 223, so it is divisible by 3.
What are the factors of 10035?
1, 3, 5, 9, 15, 45, 223, 669, 1115, 2007, 3345, 10035.
What is 10035 in binary?
10011100110011 (hexadecimal 2733, octal 23463).
What is the square root of 10035?
About 100.1748, exactly 3√1115.
Is 10035 divisible by 3?
Yes. Its digits add up to 9, a multiple of 3.
What is special about the number 10035?
10035 is a Harshad number: divisible by its digit sum 9.