Factors of 9992

2, 1249. As a product: 2^3 × 1249.

The factors of 9992 are 1, 2, 4, 8, 1249, 2498, 4996, 9992. It has 8 factors.

Factors of 9992

Pick any whole number from 1 to 10,000.

9992 = 2^{3} \times 1249

How to work it out

1
A factor of 9992 is a whole number that divides it with nothing left over. You only need to test the numbers up to √9992 ≈ 99.96; every one that divides gives a pair.
2
The factor pairs are listed in the table below. Together they give 8 factors.
3
Prime factorisation: keep dividing by the smallest prime that fits.
$9992 = 2^{3} \times 1249$
4
Add all the factors: 1 + 2 + 4 + 8 + 1249 + 2498 + 4996 + 9992 = 18750. Without 9992 itself that is 8758, so 9992 is a deficient number.

LaTeX source of the formulas on this page

\[ 9992 = 2^{3} \times 1249 \]

What are the factors of 9992?

The factors of 9992 are 1, 2, 4, 8, 1249, 2498, 4996, 9992. It has 8 factors.

What are the prime factors of 9992?

2, 1249. As a product: $2^{3}$ × 1249.

How many factors does 9992 have?

9992 has 8 factors (4 factor pairs).

What is the sum of the factors of 9992?

18750.

Is 9992 a prime number?

No. It is divisible by 2, so 9992 = 2 × 4996.