Factors of 9490
The factors of 9490 are 1, 2, 5, 10, 13, 26, 65, 73, 130, 146, 365, 730, 949, 1898, 4745, 9490. It has 16 factors.
Pick any whole number from 1 to 10,000.
How to work it out
- 1
A factor of 9490 is a whole number that divides it with nothing left over. You only need to test the numbers up to √9490 ≈ 97.42; every one that divides gives a pair.
- 2
The factor pairs are listed in the table below. Together they give 16 factors.
- 3
Prime factorisation: keep dividing by the smallest prime that fits.
- 4
Add all the factors: the sum is 18648. Without 9490 itself that is 9158, so 9490 is a deficient number.
LaTeX source of the formulas on this page
\[ 9490 = 2 \times 5 \times 13 \times 73 \]
Factor pairs of 9490
| Factor | Pairs with | Product |
|---|---|---|
| 1 | 9490 | 1 × 9490 = 9490 |
| 2 | 4745 | 2 × 4745 = 9490 |
| 5 | 1898 | 5 × 1898 = 9490 |
| 10 | 949 | 10 × 949 = 9490 |
| 13 | 730 | 13 × 730 = 9490 |
| 26 | 365 | 26 × 365 = 9490 |
| 65 | 146 | 65 × 146 = 9490 |
| 73 | 130 | 73 × 130 = 9490 |
Questions
What are the factors of 9490?
The factors of 9490 are 1, 2, 5, 10, 13, 26, 65, 73, 130, 146, 365, 730, 949, 1898, 4745, 9490. It has 16 factors.
What are the prime factors of 9490?
2, 5, 13, 73. As a product: 2 × 5 × 13 × 73.
How many factors does 9490 have?
9490 has 16 factors (8 factor pairs).
What is the sum of the factors of 9490?
18648.
Is 9490 a prime number?
No. It is divisible by 2, so 9490 = 2 × 4745.