Factors of 8012

2, 2003. As a product: 2^2 × 2003.

The factors of 8012 are 1, 2, 4, 2003, 4006, 8012. It has 6 factors.

Factors of 8012

Pick any whole number from 1 to 10,000.

8012 = 2^{2} \times 2003

How to work it out

1
A factor of 8012 is a whole number that divides it with nothing left over. You only need to test the numbers up to √8012 ≈ 89.51; every one that divides gives a pair.
2
The factor pairs are listed in the table below. Together they give 6 factors.
3
Prime factorisation: keep dividing by the smallest prime that fits.
$8012 = 2^{2} \times 2003$
4
Add all the factors: 1 + 2 + 4 + 2003 + 4006 + 8012 = 14028. Without 8012 itself that is 6016, so 8012 is a deficient number.

LaTeX source of the formulas on this page

\[ 8012 = 2^{2} \times 2003 \]

What are the factors of 8012?

The factors of 8012 are 1, 2, 4, 2003, 4006, 8012. It has 6 factors.

What are the prime factors of 8012?

2, 2003. As a product: $2^{2}$ × 2003.

How many factors does 8012 have?

8012 has 6 factors (3 factor pairs).

What is the sum of the factors of 8012?

14028.

Is 8012 a prime number?

No. It is divisible by 2, so 8012 = 2 × 4006.