Factors of 7948

2, 1987. As a product: 2^2 × 1987.

The factors of 7948 are 1, 2, 4, 1987, 3974, 7948. It has 6 factors.

Factors of 7948

Pick any whole number from 1 to 10,000.

7948 = 2^{2} \times 1987

How to work it out

1
A factor of 7948 is a whole number that divides it with nothing left over. You only need to test the numbers up to √7948 ≈ 89.15; every one that divides gives a pair.
2
The factor pairs are listed in the table below. Together they give 6 factors.
3
Prime factorisation: keep dividing by the smallest prime that fits.
$7948 = 2^{2} \times 1987$
4
Add all the factors: 1 + 2 + 4 + 1987 + 3974 + 7948 = 13916. Without 7948 itself that is 5968, so 7948 is a deficient number.

LaTeX source of the formulas on this page

\[ 7948 = 2^{2} \times 1987 \]

What are the factors of 7948?

The factors of 7948 are 1, 2, 4, 1987, 3974, 7948. It has 6 factors.

What are the prime factors of 7948?

2, 1987. As a product: $2^{2}$ × 1987.

How many factors does 7948 have?

7948 has 6 factors (3 factor pairs).

What is the sum of the factors of 7948?

13916.

Is 7948 a prime number?

No. It is divisible by 2, so 7948 = 2 × 3974.