Factors of 5537

7, 113. As a product: 7^2 × 113.

The factors of 5537 are 1, 7, 49, 113, 791, 5537. It has 6 factors.

Factors of 5537

Pick any whole number from 1 to 10,000.

5537 = 7^{2} \times 113

How to work it out

1
A factor of 5537 is a whole number that divides it with nothing left over. You only need to test the numbers up to √5537 ≈ 74.41; every one that divides gives a pair.
2
The factor pairs are listed in the table below. Together they give 6 factors.
3
Prime factorisation: keep dividing by the smallest prime that fits.
$5537 = 7^{2} \times 113$
4
Add all the factors: 1 + 7 + 49 + 113 + 791 + 5537 = 6498. Without 5537 itself that is 961, so 5537 is a deficient number.

LaTeX source of the formulas on this page

\[ 5537 = 7^{2} \times 113 \]

What are the factors of 5537?

The factors of 5537 are 1, 7, 49, 113, 791, 5537. It has 6 factors.

What are the prime factors of 5537?

7, 113. As a product: $7^{2}$ × 113.

How many factors does 5537 have?

5537 has 6 factors (3 factor pairs).

What is the sum of the factors of 5537?

6498.

Is 5537 a prime number?

No. It is divisible by 7, so 5537 = 7 × 791.