Factors of 530
The factors of 530 are 1, 2, 5, 10, 53, 106, 265, 530. It has 8 factors.
Factors of 530
Pick any whole number from 1 to 10,000.
How to work it out
- 1
A factor of 530 is a whole number that divides it with nothing left over. You only need to test the numbers up to √530 ≈ 23.02; every one that divides gives a pair.
- 2
The factor pairs are listed in the table below. Together they give 8 factors.
- 3
Prime factorisation: keep dividing by the smallest prime that fits.
- 4
Add all the factors: 1 + 2 + 5 + 10 + 53 + 106 + 265 + 530 = 972. Without 530 itself that is 442, so 530 is a deficient number.
LaTeX source of the formulas on this page
\[ 530 = 2 \times 5 \times 53 \]
Factor pairs of 530
| Factor | Pairs with | Product |
|---|---|---|
| 1 | 530 | 1 × 530 = 530 |
| 2 | 265 | 2 × 265 = 530 |
| 5 | 106 | 5 × 106 = 530 |
| 10 | 53 | 10 × 53 = 530 |
Questions
What are the factors of 530?
The factors of 530 are 1, 2, 5, 10, 53, 106, 265, 530. It has 8 factors.
What are the prime factors of 530?
2, 5, 53. As a product: 2 × 5 × 53.
How many factors does 530 have?
530 has 8 factors (4 factor pairs).
What is the sum of the factors of 530?
972.
Is 530 a prime number?
No. It is divisible by 2, so 530 = 2 × 265.