Factors of 3908

2, 977. As a product: 2^2 × 977.

The factors of 3908 are 1, 2, 4, 977, 1954, 3908. It has 6 factors.

Factors of 3908

Pick any whole number from 1 to 10,000.

3908 = 2^{2} \times 977

How to work it out

1
A factor of 3908 is a whole number that divides it with nothing left over. You only need to test the numbers up to √3908 ≈ 62.51; every one that divides gives a pair.
2
The factor pairs are listed in the table below. Together they give 6 factors.
3
Prime factorisation: keep dividing by the smallest prime that fits.
$3908 = 2^{2} \times 977$
4
Add all the factors: 1 + 2 + 4 + 977 + 1954 + 3908 = 6846. Without 3908 itself that is 2938, so 3908 is a deficient number.

LaTeX source of the formulas on this page

\[ 3908 = 2^{2} \times 977 \]

What are the factors of 3908?

The factors of 3908 are 1, 2, 4, 977, 1954, 3908. It has 6 factors.

What are the prime factors of 3908?

2, 977. As a product: $2^{2}$ × 977.

How many factors does 3908 have?

3908 has 6 factors (3 factor pairs).

What is the sum of the factors of 3908?

6846.

Is 3908 a prime number?

No. It is divisible by 2, so 3908 = 2 × 1954.