Factors of 3512

2, 439. As a product: 2^3 × 439.

The factors of 3512 are 1, 2, 4, 8, 439, 878, 1756, 3512. It has 8 factors.

Factors of 3512

Pick any whole number from 1 to 10,000.

3512 = 2^{3} \times 439

How to work it out

1
A factor of 3512 is a whole number that divides it with nothing left over. You only need to test the numbers up to √3512 ≈ 59.26; every one that divides gives a pair.
2
The factor pairs are listed in the table below. Together they give 8 factors.
3
Prime factorisation: keep dividing by the smallest prime that fits.
$3512 = 2^{3} \times 439$
4
Add all the factors: 1 + 2 + 4 + 8 + 439 + 878 + 1756 + 3512 = 6600. Without 3512 itself that is 3088, so 3512 is a deficient number.

LaTeX source of the formulas on this page

\[ 3512 = 2^{3} \times 439 \]

What are the factors of 3512?

The factors of 3512 are 1, 2, 4, 8, 439, 878, 1756, 3512. It has 8 factors.

What are the prime factors of 3512?

2, 439. As a product: $2^{3}$ × 439.

How many factors does 3512 have?

3512 has 8 factors (4 factor pairs).

What is the sum of the factors of 3512?

6600.

Is 3512 a prime number?

No. It is divisible by 2, so 3512 = 2 × 1756.