Factors of 3490
The factors of 3490 are 1, 2, 5, 10, 349, 698, 1745, 3490. It has 8 factors.
Pick any whole number from 1 to 10,000.
How to work it out
- 1
A factor of 3490 is a whole number that divides it with nothing left over. You only need to test the numbers up to √3490 ≈ 59.08; every one that divides gives a pair.
- 2
The factor pairs are listed in the table below. Together they give 8 factors.
- 3
Prime factorisation: keep dividing by the smallest prime that fits.
- 4
Add all the factors: 1 + 2 + 5 + 10 + 349 + 698 + 1745 + 3490 = 6300. Without 3490 itself that is 2810, so 3490 is a deficient number.
LaTeX source of the formulas on this page
\[ 3490 = 2 \times 5 \times 349 \]
Factor pairs of 3490
| Factor | Pairs with | Product |
|---|---|---|
| 1 | 3490 | 1 × 3490 = 3490 |
| 2 | 1745 | 2 × 1745 = 3490 |
| 5 | 698 | 5 × 698 = 3490 |
| 10 | 349 | 10 × 349 = 3490 |
Questions
What are the factors of 3490?
The factors of 3490 are 1, 2, 5, 10, 349, 698, 1745, 3490. It has 8 factors.
What are the prime factors of 3490?
2, 5, 349. As a product: 2 × 5 × 349.
How many factors does 3490 have?
3490 has 8 factors (4 factor pairs).
What is the sum of the factors of 3490?
6300.
Is 3490 a prime number?
No. It is divisible by 2, so 3490 = 2 × 1745.