Factors of 3428

2, 857. As a product: 2^2 × 857.

The factors of 3428 are 1, 2, 4, 857, 1714, 3428. It has 6 factors.

Factors of 3428

Pick any whole number from 1 to 10,000.

3428 = 2^{2} \times 857

How to work it out

1
A factor of 3428 is a whole number that divides it with nothing left over. You only need to test the numbers up to √3428 ≈ 58.55; every one that divides gives a pair.
2
The factor pairs are listed in the table below. Together they give 6 factors.
3
Prime factorisation: keep dividing by the smallest prime that fits.
$3428 = 2^{2} \times 857$
4
Add all the factors: 1 + 2 + 4 + 857 + 1714 + 3428 = 6006. Without 3428 itself that is 2578, so 3428 is a deficient number.

LaTeX source of the formulas on this page

\[ 3428 = 2^{2} \times 857 \]

What are the factors of 3428?

The factors of 3428 are 1, 2, 4, 857, 1714, 3428. It has 6 factors.

What are the prime factors of 3428?

2, 857. As a product: $2^{2}$ × 857.

How many factors does 3428 have?

3428 has 6 factors (3 factor pairs).

What is the sum of the factors of 3428?

6006.

Is 3428 a prime number?

No. It is divisible by 2, so 3428 = 2 × 1714.