Factors of 1712

2, 107. As a product: 2^4 × 107.

The factors of 1712 are 1, 2, 4, 8, 16, 107, 214, 428, 856, 1712. It has 10 factors.

Factors of 1712

Pick any whole number from 1 to 10,000.

1712 = 2^{4} \times 107

How to work it out

1
A factor of 1712 is a whole number that divides it with nothing left over. You only need to test the numbers up to √1712 ≈ 41.38; every one that divides gives a pair.
2
The factor pairs are listed in the table below. Together they give 10 factors.
3
Prime factorisation: keep dividing by the smallest prime that fits.
$1712 = 2^{4} \times 107$
4
Add all the factors: 1 + 2 + 4 + 8 + 16 + 107 + 214 + 428 + 856 + 1712 = 3348. Without 1712 itself that is 1636, so 1712 is a deficient number.

LaTeX source of the formulas on this page

\[ 1712 = 2^{4} \times 107 \]

What are the factors of 1712?

The factors of 1712 are 1, 2, 4, 8, 16, 107, 214, 428, 856, 1712. It has 10 factors.

What are the prime factors of 1712?

2, 107. As a product: $2^{4}$ × 107.

How many factors does 1712 have?

1712 has 10 factors (5 factor pairs).

What is the sum of the factors of 1712?

3348.

Is 1712 a prime number?

No. It is divisible by 2, so 1712 = 2 × 856.